Measuring Pressure — Question 6

Section 14-4 · Physics pages 2122–2123

Question 6 Tilting a barometer changes length but not vertical head An ideal barometer with negligible headspace pressure requires a vertical liquid head of 0.750 m in the current atmosphere. Its straight tube is tilted to 60◦above horizontal. The reservoir is large enough that its level does not change appreciably. h ℓ Tilted tube schematic; pressure depends on vertical head. (a) Find the liquid-column length along the tilted tube. What fraction of the true pressure would be reported if that length were mistaken for a vertical height? (b) The usable tube length above the reservoir is 0.90 m. Find the minimum angle above horizontal at which this barometer can retain a headspace under the ideal assumptions.
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Question 6 - Solution Tilting a barometer changes length but not vertical head h ℓ (a) Derivation and calculation h = ℓsin θ ⇒ℓ= .750/ sin 60◦= .866025 m . pindicated ptrue = ρgℓ ρgh = 1 sin 60◦= 1.15470 . Mistaking length for vertical head overstates pressure by 15.47%. (b) Result and interpretation For usable length L = .900 m, L sin θ ≥h ⇒θ ≥sin−1(.750/.900). θlimiting = 56.4427◦. A finite headspace requires θ > 56.4427◦; equality places the meniscus at the end of the usable tube. Physical check At 90◦, the liquid length equals the vertical head, as required.

Question 6

Tilting a barometer changes length but not vertical head

An ideal barometer with negligible headspace pressure requires a vertical liquid head of 0.750m0.750\,\mathrm{m} in the current atmosphere. Its straight tube is tilted to 60∘60^\circ above horizontal. The reservoir is large enough that its level does not change appreciably.

Diagram shown in the original SVG worksheet.

  1. Find the liquid-column length along the tilted tube. What fraction of the true pressure would be reported if that length were mistaken for a vertical height?

  2. The usable tube length above the reservoir is 0.90m0.90\,\mathrm{m}. Find the minimum angle above horizontal at which this barometer can retain a headspace under the ideal assumptions.

Question 6 - Solution

Tilting a barometer changes length but not vertical head

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

h=ℓsin⁡θ⇒ℓ=.750/sin⁡60∘=.866025m.h=\ell\sin\theta\Rightarrow\boxed{\ell=.750/\sin60^\circ=.866025\,\mathrm m}.pindicatedptrue=ρgℓρgh=1sin⁡60∘=1.15470.\boxed{\frac{p_{\mathrm{indicated}}}{p_{\mathrm{true}}}=\frac{\rho g\ell}{\rho gh}=\frac1{\sin60^\circ}=1.15470}.Mistaking length for vertical head overstates pressure by 15.47%15.47\%.

(b) Result and interpretation

For usable length L=.900mL=.900\,\mathrm m,Lsin⁡θ≥h⇒θ≥sin⁡−1(.750/.900).L\sin\theta\ge h\Rightarrow\theta\ge\sin^{-1}(.750/.900).θlimiting=56.4427∘.\boxed{\theta_{\mathrm{limiting}}=56.4427^\circ}.A finite headspace requires θ>56.4427∘\theta>56.4427^\circ; equality places the meniscus at the end of the usable tube.

Physical check

At 90∘90^\circ, the liquid length equals the vertical head, as required.