Density and Pressure — Question 6

Section 14-2 · Physics pages 2082–2083

Question 6 A negative gauge reading can still mean positive absolute pressure A sealed chamber has uniform absolute pressure 82 kPa; outside pressure is 101 kPa. A flat hatch of area 0.025 m2 separates them. Ignore its weight and hinge friction. p1A p2A area A Pressure forces act normally on the two sides; their difference gives the net force. (a) Find chamber gauge pressure and the net pressure force on the hatch, including direction. (b) Outside pressure later falls to 76 kPa while chamber pressure remains fixed. Find the new net force and explain what has reversed.
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Question 6 - Solution A negative gauge reading can still mean positive absolute pressure p1A p2A area A (a) Derivation and calculation Take outward as positive: pg = pin −pout = 82 −101 = −19 kPa . Fnet = pgA = (−19000)(.025) = −475 N . The net force is 475 N inward although both absolute pressures are positive. (b) Result and interpretation After the outside pressure falls, ∆p = 82 −76 = +6 kPa. Fnet = 6000(.025) = +150 N outward . The pressure ordering reverses; the chamber absolute pressure remains 82 kPa. Physical check A gauge value is a pressure difference, so a negative reading does not mean a negative absolute pressure.

Question 6

A negative gauge reading can still mean positive absolute pressure

A sealed chamber has uniform absolute pressure 82kPa82\,\mathrm{kPa}; outside pressure is 101kPa101\,\mathrm{kPa}. A flat hatch of area 0.025m20.025\,\mathrm{m^2} separates them. Ignore its weight and hinge friction.

Diagram shown in the original SVG worksheet.

  1. Find chamber gauge pressure and the net pressure force on the hatch, including direction.

  2. Outside pressure later falls to 76kPa76\,\mathrm{kPa} while chamber pressure remains fixed. Find the new net force and explain what has reversed.

Question 6 - Solution

A negative gauge reading can still mean positive absolute pressure

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Take outward as positive:pg=pin−pout=82−101=−19kPa.p_g=p_{\mathrm{in}}-p_{\mathrm{out}}=82-101=\boxed{-19\,\mathrm{kPa}}.Fnet=pgA=(−19000)(.025)=−475N.\boxed{F_{\mathrm{net}}=p_gA=(-19000)(.025)=-475\,\mathrm N}.The net force is 475 N inward although both absolute pressures are positive.

(b) Result and interpretation

After the outside pressure falls,Δp=82−76=+6kPa.\Delta p=82-76=+6\,\mathrm{kPa}.Fnet=6000(.025)=+150Noutward.\boxed{F_{\mathrm{net}}=6000(.025)=+150\,\mathrm N\ \text{outward}}.The pressure ordering reverses; the chamber absolute pressure remains 82 kPa.

Physical check

A gauge value is a pressure difference, so a negative reading does not mean a negative absolute pressure.