What Is a Fluid? — Question 10

Section 14-1 · Physics pages 2070–2071

Question 10 A sliding boundary can imitate a flowing sample Two shear tests give the same top-plate displacement, xtop = 1.0 mm, while the bottom plate is fixed. The gap is h = 10 mm. Tracer displacements inside sample A are xA(y) = 0.10y for 0 ≤y ≤h, with both quantities measured in millimeters. Tracers inside B all have xB(y) = 1.0 mm. The displacement is horizontal; y measures height above the bottom plate. y x A B h 1.0 mm Displacement profiles x(y), not physical trajectories; curves are schematic. (a) Calculate the relative displacement of tracers at y = 2 mm and 8 mm for each sample. Which sample has demonstrated internal shear deformation, and where must B have slipped? (b) Does the internal displacement pattern of A at this single instant prove it is a fluid? Specify the added observation needed for a convincing fluid-like response test.
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Question 10 - Solution A sliding boundary can imitate a flowing sample y x A B h 1.0 mm (a) Derivation and calculation ∆xA = xA(8) −xA(2) = .10(8 −2) = .60 mm . ∆xB = 1.0 −1.0 = 0 . dxA dy = .10, dxB dy = 0. A demonstrates internal shear; B translates rigidly. (b) Result and interpretation At the lower boundary, xB(0) −xbottom = 1.0 −0 = 1.0 mm ⇒bottom-boundary slip. A single nonzero shear strain does not prove fluid behavior. Maintain a small nonzero load and measure the evolution of internal strain while checking slip: γ(t) →γ∞versus continued growth of γ(t). Physical check An elastic solid can exhibit the same instantaneous sheared shape; the time-dependent response supplies the missing evidence.

Question 10

A sliding boundary can imitate a flowing sample

Two shear tests give the same top-plate displacement, xtop=1.0mmx_{\mathrm{top}}=1.0\,\mathrm{mm}, while the bottom plate is fixed. The gap is h=10mmh=10\,\mathrm{mm}. Tracer displacements inside sample A are xA(y)=0.10yx_A(y)=0.10y for 0≤y≤h0\le y\le h, with both quantities measured in millimeters. Tracers inside B all have xB(y)=1.0mmx_B(y)=1.0\,\mathrm{mm}. The displacement is horizontal; yy measures height above the bottom plate.

Diagram shown in the original SVG worksheet.

  1. Calculate the relative displacement of tracers at y=2mmy=2\,\mathrm{mm} and 8mm8\,\mathrm{mm} for each sample. Which sample has demonstrated internal shear deformation, and where must B have slipped?

  2. Does the internal displacement pattern of A at this single instant prove it is a fluid? Specify the added observation needed for a convincing fluid-like response test.

Question 10 - Solution

A sliding boundary can imitate a flowing sample

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

ΔxA=xA(8)−xA(2)=.10(8−2)=.60mm.\Delta x_A=x_A(8)-x_A(2)=.10(8-2)=\boxed{.60\,\mathrm{mm}}.ΔxB=1.0−1.0=0.\Delta x_B=1.0-1.0=\boxed0.dxAdy=.10,dxBdy=0.\frac{dx_A}{dy}=.10,\qquad\frac{dx_B}{dy}=0.A demonstrates internal shear; B translates rigidly.

(b) Result and interpretation

At the lower boundary,xB(0)−xbottom=1.0−0=1.0mmx_B(0)-x_{\mathrm{bottom}}=1.0-0=\boxed{1.0\,\mathrm{mm}}⇒bottom-boundary slip.\Rightarrow\text{bottom-boundary slip}.A single nonzero shear strain does not prove fluid behavior. Maintain a small nonzero load and measure the evolution of internal strain while checking slip:γ(t)→γ∞versus continued growth of γ(t).\gamma(t)\to\gamma_\infty\ \text{versus continued growth of }\gamma(t).

Physical check

An elastic solid can exhibit the same instantaneous sheared shape; the time-dependent response supplies the missing evidence.