What Is a Fluid? — Question 7

Section 14-1 · Physics pages 2064–2065

Question 7 What a motion detector can and cannot prove A top plate is pulled by a constant nonzero tangential force while the bottom plate remains fixed. A detector reports no resolved relative displacement during 120 s and can resolve a displacement of 0.010 mm or larger. Assume any fluid-like displacement would be monotonic, with no initial transient, drift or slip. t (s) x (mm) .010 500 120 Candidate constant-speed displacement and the detector threshold. (a) Find the upper bound on the mean relative speed consistent with the report. Can the report prove that the sample is an elastic solid? (b) A candidate fluid would move at 2.0 × 10−8 m/s under this load. Find the minimum duration needed to reach the detector threshold. Explain what a longer null result could and could not establish.
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Question 7 - Solution What a motion detector can and cannot prove t (s) x (mm) .010 500 120 (a) Derivation and calculation |∆x| < .010 mm = 1.0 × 10−5 m. |¯v| < 1.0 × 10−5 120 = 8.33 × 10−8 m/s . This bound permits both zero speed and slower continued deformation; it cannot prove a solid response. (b) Result and interpretation For the candidate speed, tthreshold = 1.0 × 10−5 2.0 × 10−8 = 500 s . x(120) = 2.4 × 10−6 m = .0024 mm < .010 mm. A null result at 500 s rules out this candidate under the stated assumptions, but not every slower fluid response. Physical check The detector resolves displacement at the threshold itself, so the minimum duration is inclusive.

Question 7

What a motion detector can and cannot prove

A top plate is pulled by a constant nonzero tangential force while the bottom plate remains fixed. A detector reports no resolved relative displacement during 120s120\,\mathrm{s} and can resolve a displacement of 0.010mm0.010\,\mathrm{mm} or larger. Assume any fluid-like displacement would be monotonic, with no initial transient, drift or slip.

Diagram shown in the original SVG worksheet.

  1. Find the upper bound on the mean relative speed consistent with the report. Can the report prove that the sample is an elastic solid?

  2. A candidate fluid would move at 2.0×10−8m/s2.0\times10^{-8}\,\mathrm{m/s} under this load. Find the minimum duration needed to reach the detector threshold. Explain what a longer null result could and could not establish.

Question 7 - Solution

What a motion detector can and cannot prove

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

|Δx|<.010mm=1.0×10−5m.|\Delta x|<.010\,\mathrm{mm}=1.0\times10^{-5}\,\mathrm m.|v‾|<1.0×10−5120=8.33×10−8m/s.\boxed{|\bar v|<\frac{1.0\times10^{-5}}{120}=8.33\times10^{-8}\,\mathrm{m/s}}.This bound permits both zero speed and slower continued deformation; it cannot prove a solid response.

(b) Result and interpretation

For the candidate speed,tthreshold=1.0×10−52.0×10−8=500s.\boxed{t_{\mathrm{threshold}}=\frac{1.0\times10^{-5}}{2.0\times10^{-8}}=500\,\mathrm s}.x(120)=2.4×10−6m=.0024mm<.010mm.x(120)=2.4\times10^{-6}\,\mathrm m=.0024\,\mathrm{mm}<.010\,\mathrm{mm}.A null result at 500 s rules out this candidate under the stated assumptions, but not every slower fluid response.

Physical check

The detector resolves displacement at the threshold itself, so the minimum duration is inclusive.