Some Examples of Static Equilibrium — Question 6

Section 12-4 · Physics pages 1842–1843

Question 6 Separated door hinges supply a horizontal force couple A door of weight 300 N has its center 0.40 m horizontally from its vertical hinge line. Two hinges lie 1.50 m apart vertically. Model each hinge as a force connection with no individual couple; the door is static. W Door-plane view; horizontal hinge reactions form a counteracting couple. (a) Find the horizontal reaction components in the plane of the door. (b) Can equilibrium alone determine the vertical force carried by each hinge?
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Question 6 - Solution Separated door hinges supply a horizontal force couple W (a) Derivation and calculation Let Hu, Hl denote horizontal hinge forces, positive away from the hinge line. The weight produces moment Wb = 300(.40) = 120 N m. The hinge couple must oppose it: Hl(1.50) = 120 =⇒ Hl = 80 N . Horizontal balance gives Hu = −80 N . (b) Result and interpretation The vertical reactions satisfy only Vu + Vl = 300 N . Any pair Vu = q, Vl = 300 −q satisfies rigid-body balance. Because both act on the same vertical hinge line, their split does not alter the relevant moment. Hinge stiffness or fit information is required to determine q. Physical check The upper horizontal force points toward the hinge line and the lower one away from it, giving the required counterclockwise couple.

Question 6

Separated door hinges supply a horizontal force couple

A door of weight 300N300\,\mathrm N has its center 0.40m0.40\,\mathrm m horizontally from its vertical hinge line. Two hinges lie 1.50m1.50\,\mathrm m apart vertically. Model each hinge as a force connection with no individual couple; the door is static.

Diagram shown in the original SVG worksheet.

  1. Find the horizontal reaction components in the plane of the door.

  2. Can equilibrium alone determine the vertical force carried by each hinge?

Question 6 - Solution

Separated door hinges supply a horizontal force couple

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Let Hu,HlH_u,H_l denote horizontal hinge forces, positive away from the hinge line. The weight produces moment Wb=300(.40)=120Nm.Wb=300(.40)=120\ \mathrm{N\,m}. The hinge couple must oppose it: Hl(1.50)=120⇒Hl=80N.H_l(1.50)=120\quad\Longrightarrow\quad\boxed{H_l=80\ \mathrm N}. Horizontal balance gives Hu=−80N\boxed{H_u=-80\ \mathrm N}.

(b) Result and interpretation

The vertical reactions satisfy only Vu+Vl=300N.\boxed{V_u+V_l=300\ \mathrm N}. Any pair Vu=qV_u=q, Vl=300−qV_l=300-q satisfies rigid-body balance. Because both act on the same vertical hinge line, their split does not alter the relevant moment. Hinge stiffness or fit information is required to determine qq.

Physical check

The upper horizontal force points toward the hinge line and the lower one away from it, giving the required counterclockwise couple.