Are Angular Quantities Vectors? — Question 7

Section 10-2 · Physics pages 1404–1405

Question 7 A proper change of axes preserves the angular vector magnitude A rotor has⃗ω = (3, 4, 0) rad/s. New right-handed axes are ˆe1 = (4/5, −3/5, 0), ˆe2 = (3/5, 4/5, 0) and ˆe3 = ˆz. x y ˆe1 ˆe2⃗ ω The new orthonormal axes are rotated within the laboratory xy plane. (a) Find the angular-velocity components in the new axes. (b) Find the new components of⃗α = (1, −2, 0) rad/s2 and decide whether the angular speed is increasing.
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Question 7 - Solution A proper change of axes preserves the angular vector magnitude x y ˆe1 ˆe2⃗ ω (a) Derivation and calculation Components in an orthonormal basis are scalar projections: ω1 =⃗ω · ˆe1 = 12 −12 5 = 0, ω2 = 9 + 16 5 = 5, ω3 = 0.⃗ ω′ = (0, 5, 0) rad/s , |⃗ω′| = |⃗ω| = 5. (b) Result and interpretation Project acceleration in the same basis: α1 = 4 + 6 5 = 2, α2 = 3 −8 5 = −1,⃗ α′ = (2, −1, 0) rad/s2 . d|ω| dt =⃗ω ·⃗α |ω| = 3 −8 5 = −1 rad/s2 . The rotor slows; the new components give the same dot product 0(2) + 5(−1) = −5. Physical check A proper orthonormal change of axes preserves both vector magnitudes and dot products.

Question 7

A proper change of axes preserves the angular vector magnitude

A rotor has ω→=(3,4,0)rad/s\vec\omega=(3,4,0)\,\mathrm{rad/s}. New right-handed axes are ê1=(4/5,−3/5,0)\hat e_1=(4/5,-3/5,0), ê2=(3/5,4/5,0)\hat e_2=(3/5,4/5,0) and ê3=ẑ\hat e_3=\hat z.

Diagram shown in the original SVG worksheet.

  1. Find the angular-velocity components in the new axes.

  2. Find the new components of α→=(1,−2,0)rad/s2\vec\alpha=(1,-2,0)\,\mathrm{rad/s^2} and decide whether the angular speed is increasing.

Question 7 - Solution

A proper change of axes preserves the angular vector magnitude

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Components in an orthonormal basis are scalar projections: ω1=ω→⋅ê1=12−125=0,ω2=9+165=5,ω3=0.\omega_1=\vec\omega\cdot\hat e_1=\frac{12-12}{5}=0,\qquad \omega_2=\frac{9+16}{5}=5,\qquad\omega_3=0. ω→′=(0,5,0)rad/s,|ω→′|=|ω→|=5.\boxed{\vec\omega^{\prime}=(0,5,0)\ \mathrm{rad/s}},\qquad |\vec\omega^{\prime}|=|\vec\omega|=5.

(b) Result and interpretation

Project acceleration in the same basis: α1=4+65=2,α2=3−85=−1,α→′=(2,−1,0)rad/s2.\alpha_1=\frac{4+6}{5}=2,\qquad\alpha_2=\frac{3-8}{5}=-1, \qquad\boxed{\vec\alpha^{\prime}=(2,-1,0)\ \mathrm{rad/s^2}}. d|ω|dt=ω→⋅α→|ω|=3−85=−1rad/s2.\frac{d|\omega|}{dt}=\frac{\vec\omega\cdot\vec\alpha}{|\omega|} =\frac{3-8}{5}=\boxed{-1\ \mathrm{rad/s^2}}. The rotor slows; the new components give the same dot product 0(2)+5(−1)=−50(2)+5(-1)=-5.

Physical check

A proper orthonormal change of axes preserves both vector magnitudes and dot products.