Are Angular Quantities Vectors? — Question 5

Section 10-2 · Physics pages 1400–1401

Question 5 An inclined rotation axis requires a unit direction A rotor turns right-handed about an axis pointing along (2, −1, 2), at angular speed 9 rad/s. Its speed increases at 3 rad/s2 without changing axis direction. x y z ˆn ∥(2, −1, 2) The rotation vector lies along an inclined axis; normalize the direction before assigning its magnitude. (a) Find angular velocity and angular acceleration in Cartesian components. (b) Explain why multiplying (2, −1, 2) directly by 9 gives the wrong angular speed.
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Question 5 - Solution An inclined rotation axis requires a unit direction x y z ˆn ∥(2, −1, 2) (a) Derivation and calculation Normalize the specified direction: |⃗d| = √ 22 + (−1)2 + 22 = 3, ˆn = 1 3(2, −1, 2).⃗ ω = 9ˆn = (6, −3, 6) rad/s ,⃗ α = 3ˆn = (2, −1, 2) rad/s2 . (b) Result and interpretation Multiplication by the unnormalized direction gives |9⃗d| = 9|⃗d| = 27 rad/s̸ = 9 rad/s. The required check is |⃗ω| = √ 36 + 9 + 36 = 9, |⃗α| = √ 4 + 1 + 4 = 3. Physical check Both vectors are parallel because the axis direction is fixed while the speed increases.

Question 5

An inclined rotation axis requires a unit direction

A rotor turns right-handed about an axis pointing along (2,−1,2)(2,-1,2), at angular speed 9rad/s9\,\mathrm{rad/s}. Its speed increases at 3rad/s23\,\mathrm{rad/s^2} without changing axis direction.

Diagram shown in the original SVG worksheet.

  1. Find angular velocity and angular acceleration in Cartesian components.

  2. Explain why multiplying (2,−1,2)(2,-1,2) directly by 9 gives the wrong angular speed.

Question 5 - Solution

An inclined rotation axis requires a unit direction

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Normalize the specified direction: |d→|=22+(−1)2+22=3,n̂=13(2,−1,2).|\vec d|=\sqrt{2^2+(-1)^2+2^2}=3,\qquad\hat n=\frac13(2,-1,2). ω→=9n̂=(6,−3,6)rad/s,α→=3n̂=(2,−1,2)rad/s2.\boxed{\vec\omega=9\hat n=(6,-3,6)\ \mathrm{rad/s}},\qquad \boxed{\vec\alpha=3\hat n=(2,-1,2)\ \mathrm{rad/s^2}}.

(b) Result and interpretation

Multiplication by the unnormalized direction gives |9d→|=9|d→|=27rad/s≠9rad/s.|9\vec d|=9|\vec d|=27\ \mathrm{rad/s}\ne9\ \mathrm{rad/s}. The required check is |ω→|=36+9+36=9,|α→|=4+1+4=3.|\vec\omega|=\sqrt{36+9+36}=9,\qquad|\vec\alpha|=\sqrt{4+1+4}=3.

Physical check

Both vectors are parallel because the axis direction is fixed while the speed increases.