Are Angular Quantities Vectors? — Question 3

Section 10-2 · Physics pages 1396–1397

Question 3 Finite rotations fail the ordinary vector addition test A body-fixed arrow initially points along +z. Apply right-handed 90◦rotations about fixed laboratory axes. Sequence A is first about x, then about y; sequence B uses the reverse order. A: B: +z −y −y +z +x +x Rx Ry Ry Rx Each arrow applies a right-handed 90-degree rotation about a fixed laboratory axis. (a) Find the final arrow direction for each sequence. (b) Explain what this shows about treating arbitrary finite angular displacements as ordinary vectors.
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Question 3 - Solution Finite rotations fail the ordinary vector addition test A: B: +z −y −y +z +x +x Rx Ry Ry Rx (a) Derivation and calculation Act on the initial unit vector in the stated order: ˆz Rx(π/2) −−−−−→−ˆy Ry(π/2) −−−−−→−ˆy, ˆuA = −ˆy . ˆz Ry(π/2) −−−−−→ˆx Rx(π/2) −−−−−→ˆx, ˆuB = ˆx . (b) Result and interpretation A rotation about an axis leaves a vector along that axis unchanged. The two compositions therefore satisfy RyRxˆz = −ˆy̸ = ˆx = RxRyˆz. Ordinary addition obeys⃗a +⃗b =⃗b +⃗a; arbitrary finite rotations fail this test and cannot be added as ordinary vectors. Physical check The final directions are perpendicular, making the order dependence explicit.

Question 3

Finite rotations fail the ordinary vector addition test

A body-fixed arrow initially points along +z+z. Apply right-handed 90∘90^\circ rotations about fixed laboratory axes. Sequence A is first about xx, then about yy; sequence B uses the reverse order.

Diagram shown in the original SVG worksheet.

  1. Find the final arrow direction for each sequence.

  2. Explain what this shows about treating arbitrary finite angular displacements as ordinary vectors.

Question 3 - Solution

Finite rotations fail the ordinary vector addition test

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Act on the initial unit vector in the stated order: ẑ→Rx(π/2)−ŷ→Ry(π/2)−ŷ,ûA=−ŷ.\hat z\xrightarrow{R_x(\pi/2)}-\hat y \xrightarrow{R_y(\pi/2)}-\hat y,\qquad\boxed{\hat u_A=-\hat y}. ẑ→Ry(π/2)x̂→Rx(π/2)x̂,ûB=x̂.\hat z\xrightarrow{R_y(\pi/2)}\hat x \xrightarrow{R_x(\pi/2)}\hat x,\qquad\boxed{\hat u_B=\hat x}.

(b) Result and interpretation

A rotation about an axis leaves a vector along that axis unchanged. The two compositions therefore satisfy RyRxẑ=−ŷ≠x̂=RxRyẑ.R_yR_x\hat z=-\hat y\ne\hat x=R_xR_y\hat z. Ordinary addition obeys a→+b→=b→+a→\vec a+\vec b=\vec b+\vec a; arbitrary finite rotations fail this test and cannot be added as ordinary vectors.

Physical check

The final directions are perpendicular, making the order dependence explicit.