The Rotational Variables — Question 6

Section 10-1 · Physics pages 1382–1383

Question 6 Sampling can disguise a rapidly turning rotor A strobe flashes every 0.10 s. A single mark appears 30◦farther counterclockwise at each flash, modulo one turn. Assume constant angular velocity. x y + Stroboscopic orientations reveal a 30-degree increment modulo complete turns. (a) Find every angular velocity consistent with the observations. (b) If independent information gives |ω| < 20 rad/s, identify the unique value.
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Question 6 - Solution Sampling can disguise a rapidly turning rotor x y + (a) Derivation and calculation The sampled increment includes an unknown whole number of turns: ∆θk = π 6 + 2πk, k ∈Z. ωk = ∆θk 0.10 = 5π 3 + 20πk rad/s . (b) Result and interpretation Apply the independent speed bound: −20 < 5π 3 + 20πk < 20 =⇒ −0.402 < k < 0.235. k = 0, ω = 5.236 rad/s . All other integer branches are rejected by the bound. Physical check Adjacent possible rates differ by 2π/∆t = 20π rad/s, more than the full allowed speed interval.

Question 6

Sampling can disguise a rapidly turning rotor

A strobe flashes every 0.10s0.10\,\mathrm s. A single mark appears 30∘30^\circ farther counterclockwise at each flash, modulo one turn. Assume constant angular velocity.

Diagram shown in the original SVG worksheet.

  1. Find every angular velocity consistent with the observations.

  2. If independent information gives |ω|<20rad/s|\omega|<20\,\mathrm{rad/s}, identify the unique value.

Question 6 - Solution

Sampling can disguise a rapidly turning rotor

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

The sampled increment includes an unknown whole number of turns: Δθk=π6+2πk,k∈ℤ.\Delta\theta_k=\frac{\pi}{6}+2\pi k,\qquad k\in\mathbb Z. ωk=Δθk0.10=5π3+20πkrad/s.\boxed{\omega_k=\frac{\Delta\theta_k}{0.10} =\frac{5\pi}{3}+20\pi k\ \mathrm{rad/s}}.

(b) Result and interpretation

Apply the independent speed bound: −20<5π3+20πk<20⇒−0.402<k<0.235.-20<\frac{5\pi}{3}+20\pi k<20 \quad\Longrightarrow\quad -0.402<k<0.235. k=0,ω=5.236rad/s.\boxed{k=0,\qquad\omega=5.236\ \mathrm{rad/s}}. All other integer branches are rejected by the bound.

Physical check

Adjacent possible rates differ by 2π/Δt=20π2\pi/\Delta t=20\pi rad/s, more than the full allowed speed interval.