Show solutionHide solution+ Question 5 Determine whether the integral converges: ∫2∞dxxlnx.\int_2^\infty\frac{dx}{x\ln x}. Question 5 – Solution Step 1: Replace infinity with a limit. I=limb→∞∫2bdxxlnx.I=\lim_{b\to\infty}\int_2^b\frac{dx}{x\ln x}. Step 2: Substitute u=lnxu=\ln x. Then du=dxx.du=\frac{dx}{x}. The bounds become u=ln2u=\ln2 and u=lnbu=\ln b, so I=limb→∞∫ln2lnbduu=limb→∞[lnu]ln2lnb=limb→∞(ln(lnb)−ln(ln2)).\begin{align*} I&=\lim_{b\to\infty}\int_{\ln2}^{\ln b}\frac{du}{u}\\ &=\lim_{b\to\infty}[\ln u]_{\ln2}^{\ln b}\\ &=\lim_{b\to\infty}\left(\ln(\ln b)-\ln(\ln2)\right). \end{align*} Step 3: Evaluate the limit. Since ln(lnb)→∞\ln(\ln b)\to\infty, the integral diverges. diverges\boxed{\text{diverges}}