Integration Strategy — Question 8

Section 8-7 · Calculus pages 1555–1556

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Question 8

State the structural cue, then evaluate: ∫sin⁡xcos⁡4xdx.\int\sin x\cos^4x\,dx.

Question 8 – Solution

Step 1: Identify the structural cue. The sine power is odd, and sin⁡xdx\sin x\,dx is the differential of −cos⁡x-\cos x. Keep the sine factor and use the cosine as the substitution.

Step 2: Substitute u=cos⁡xu=\cos x. Then du=−sin⁡xdx,sin⁡xdx=−du.du=-\sin x\,dx,\qquad \sin x\,dx=-du. Step 3: Rewrite and integrate. ∫sin⁡xcos⁡4xdx=−∫u4du=−u55+C.\begin{align*} \int\sin x\cos^4x\,dx &=-\int u^4\,du\\ &=-\frac{u^5}{5}+C. \end{align*} Step 4: Return to xx. −15cos⁡5x+C\boxed{-\frac15\cos^5x+C}