Proof of Various Derivative Properties — Question 7

Section 7-2 · Calculus pages 1273–1274

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Question 7

Prove that the derivative of a constant function is zero. That is, if f(x)=cf(x)=c for all xx, where cc is a constant, then f′(a)=0f'(a)=0 for every real number aa.

Question 7 - Solution

By definition of the derivative, f′(a)=limh→0f(a+h)−f(a)h.f'(a)=\lim_{h\to 0}\frac{f(a+h)-f(a)}{h}.

Since f(x)=cf(x)=c for all xx, we have f(a+h)=candf(a)=c.f(a+h)=c \quad\text{and}\quad f(a)=c.

Substitute into the difference quotient: f′(a)=limh→0c−ch.f'(a) = \lim_{h\to 0}\frac{c-c}{h}.

Simplify the numerator: f′(a)=limh→00h.f'(a)=\lim_{h\to 0}\frac{0}{h}.

Since 0h=0\frac{0}{h}=0 for all h≠0h\neq 0, the limit is f′(a)=0.f'(a)=0.

Therefore, the derivative of a constant function is zero: f′(a)=0.\boxed{f'(a)=0}.