The Mean Value Theorem — Question 1

Section 4-7 · Calculus pages 795–796

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Question 1

Let f(x)=x2+2xf(x) = x^2 + 2x

(a) Verify that f(x)f(x) satisfies the hypotheses of the Mean Value Theorem on the interval [1,4][1,4].

(b) Find all numbers c∈(1,4)c \in (1,4) that satisfy the conclusion of the Mean Value Theorem.

Question 1 - Solution

We are given f(x)=x2+2xf(x) = x^2 + 2x

(a) Verifying the hypotheses

The function f(x)f(x) is a polynomial, so it is continuous on the closed interval [1,4][1,4] and differentiable on the open interval (1,4)(1,4).

Therefore, the hypotheses of the Mean Value Theorem are satisfied.

(b) Applying the Mean Value Theorem

First compute the derivative: f′(x)=2x+2f'(x) = 2x + 2

Next compute the average rate of change of ff on [1,4][1,4]: f(4)−f(1)4−1=(16+8)−(1+2)3=213=7\frac{f(4) - f(1)}{4 - 1} = \frac{(16 + 8) - (1 + 2)}{3} = \frac{21}{3} = 7

Set the derivative equal to this value: 2c+2=7⇒2c=5⇒c=522c + 2 = 7 \Rightarrow 2c = 5 \Rightarrow c = \frac{5}{2}

Thus, the number that satisfies the conclusion of the Mean Value Theorem is c=52\boxed{c = \frac{5}{2}}

Graph of f(x)f(x), the secant line, and the tangent line at cc

Diagram shown in the original SVG worksheet.