Show solutionHide solution+ Question 5 Let f(x)=etan(x3+1)f(x) = e^{\tan(x^3 + 1)}. Use the chain rule to find f′(x)f'(x). Clearly identify each function used in the composition and the order in which the chain rule is applied. Question 5 - Solution We are given: f(x)=etan(x3+1)f(x) = e^{\tan(x^3 + 1)} This is a composition of multiple functions. Let’s break it down: Outer function: u=evu = e^v Middle function: v=tan(w)v = \tan(w) Inner function: w=x3+1w = x^3 + 1 Using the chain rule: f′(x)=ddx[etan(x3+1)]=etan(x3+1)⋅ddx[tan(x3+1)]f'(x) = \frac{d}{dx} \left[ e^{\tan(x^3 + 1)} \right] = e^{\tan(x^3 + 1)} \cdot \frac{d}{dx} \left[ \tan(x^3 + 1) \right] Now, ddx[tan(x3+1)]=sec2(x3+1)⋅ddx[x3+1]=sec2(x3+1)⋅3x2\frac{d}{dx} \left[ \tan(x^3 + 1) \right] = \sec^2(x^3 + 1) \cdot \frac{d}{dx}[x^3 + 1] = \sec^2(x^3 + 1) \cdot 3x^2 Putting it all together: f′(x)=etan(x3+1)⋅sec2(x3+1)⋅3x2f'(x) = e^{\tan(x^3 + 1)} \cdot \sec^2(x^3 + 1) \cdot 3x^2 f′(x)=3x2⋅sec2(x3+1)⋅etan(x3+1)\boxed{ f'(x) = 3x^2 \cdot \sec^2(x^3 + 1) \cdot e^{\tan(x^3 + 1)} }