Derivatives of Hyperbolic Functions — Question 5

Section 3-8 · Calculus pages 561–562

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Question 5

Let f(x)=sinh⁡(x)cosh⁡(x)f(x) = \frac{\sinh(x)}{\cosh(x)}.

  • Simplify the function if possible.

  • Find f′(x)f'(x).

  • Determine the intervals where f(x)f(x) is increasing or decreasing.

Question 5 - Solution

(a) Simplify the Function:

We have: f(x)=sinh⁡(x)cosh⁡(x)f(x) = \frac{\sinh(x)}{\cosh(x)}

This is the definition of the hyperbolic tangent function: f(x)=tanh⁡(x)f(x) = \tanh(x)

(b) Differentiate f(x)=tanh⁡(x)f(x) = \tanh(x):

The derivative of tanh⁡(x)\tanh(x) is: f′(x)=sech2(x)f'(x) = \text{sech}^2(x)

(c) Increasing/Decreasing Intervals:

Since f′(x)=sech2(x)>0f'(x) = \text{sech}^2(x) > 0 for all real xx, the function is strictly increasing on its entire domain.

Conclusion: f′(x)=sech2(x),f(x) is increasing on (−∞,∞)\boxed{f'(x) = \text{sech}^2(x), \quad f(x) \text{ is increasing on } (-\infty, \infty)}