Differentiation Formulas — Question 2

Section 3-3 · Calculus pages 453–454

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Question 2

Let f(x)=x2+3x+1x2+3x.f(x) = \sqrt{x^2 + 3x} + \frac{1}{\sqrt{x^2 + 3x}}.

  • Compute f′(x)f'(x) using differentiation rules.

  • Determine all points where the derivative does not exist.

Question 2 - Solution

Domain. Set u=x2+3x=x(x+3)u=x^2+3x=x(x+3). The reciprocal square root requires u>0u>0, so

D=(−∞,−3)∪(0,∞).D=(-\infty,-3)\cup(0,\infty).

Differentiate.

f=u1/2+u−1/2,f′(x)=(2x+3)(x2+3x−1)2(x2+3x)3/2,x∈D.f=u^{1/2}+u^{-1/2},\qquad \boxed{f'(x)=\frac{(2x+3)(x^2+3x-1)}{2(x^2+3x)^{3/2}}},\quad x\in D.

The derivative exists at every point of the function’s domain. On [−3,0][-3,0], the function itself is undefined; these are not nondifferentiable points of its graph.