Limits at Infinity, Part I — Question 5

Section 2-7 · Calculus pages 339–340

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Question 5

Determine the limit: limx→∞5x4−3x2+x+12x3+4x−7\lim_{x \to \infty} \frac{5x^4 - 3x^2 + x + 1}{2x^3 + 4x - 7}

Question 5 - Solution

We are given: limx→∞5x4−3x2+x+12x3+4x−7\lim_{x \to \infty} \frac{5x^4 - 3x^2 + x + 1}{2x^3 + 4x - 7}

Step 1: Compare the degrees of the numerator and denominator.

Degree of numerator: 4 , Degree of denominator: 3

Since the degree of the numerator is greater than the degree of the denominator, the limit is infinite (the function diverges).

Step 2: Determine the sign of the infinity.

As x→∞x \to \infty, both numerator and denominator are positive: 5x4+smaller terms2x3+smaller terms>0\frac{5x^4 + \text{smaller terms}}{2x^3 + \text{smaller terms}} > 0

So the limit tends to: +∞\boxed{+\infty}