Parametric Surfaces β€” Question 7

Section 19-2 Β· Calculus pages 3513–3514

Show solutionHide solution

Question 7

Consider 𝒓(u,v)=⟨u2,v,u3⟩,βˆ’1≀u≀1,βˆ’1≀v≀1.\mathbf r(u,v)=\langle u^2,v,u^3\rangle, \qquad -1\le u\le 1,\qquad -1\le v\le 1.

Tasks

  1. Eliminate uu to find an implicit relation between xx and zz.

  2. Determine where the parametrization is regular.

  3. Explain the geometric significance of the failure set.

Question 7 – Solution

Strategy. Compare x=u2x=u^2 and z=u3z=u^3, then locate zeros of the tangent cross product.

Step 1: Eliminate the parameter z2=u6=(u2)3=x3,xβ‰₯0.z^2=u^6=(u^2)^3=x^3, \qquad x\ge 0. The image is the patch of the cuspidal cylinder z2=x3z^2=x^3 with 0≀x≀10\le x\le 1 and βˆ’1≀y≀1-1\le y\le 1.

Step 2: Test regularity 𝒓u=⟨2u,0,3u2⟩,𝒓v=⟨0,1,0⟩,\mathbf r_u=\langle 2u,0,3u^2\rangle, \qquad \mathbf r_v=\langle 0,1,0\rangle, so 𝒓u×𝒓v=βŸ¨βˆ’3u2,0,2u⟩.\mathbf r_u\times\mathbf r_v=\langle-3u^2,0,2u\rangle. This vector vanishes exactly when u=0u=0. Therefore the parametrization is regular for uβ‰ 0u\ne 0 and singular along 𝒓(0,v)=⟨0,v,0⟩.\boxed{\mathbf r(0,v)=\langle 0,v,0\rangle}.

Diagram shown in the original SVG worksheet.

Step 3: Interpret That line is the sharp cuspidal edge. At it, the uu-direction tangent collapses to zero, so the two tangent vectors cannot span a tangent plane.

Verification For u≠0u\ne 0, the third component 2u2u of the cross product is nonzero, proving regularity away from the edge.