Curl and Divergence โ€” Question 1

Section 19-1 ยท Calculus pages 3481โ€“3482

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Question 1

For ๐‘ญ(x,y,z)=โŸจx2y,yz2,xzโŸฉ,\mathbf F(x,y,z)=\langle x^2y,\,yz^2,\,xz\rangle, compute โˆ‡โ‹…๐‘ญ\nabla\cdot\mathbf F and โˆ‡ร—๐‘ญ\nabla\times\mathbf F.

Tasks

  1. Compute the divergence term by term.

  2. Compute all three components of the curl.

  3. Evaluate both quantities at (1,2,โˆ’1)(1,2,-1).

Question 1 โ€“ Solution

Strategy. Label the components P,Q,RP,Q,R and apply the divergence and curl formulas in a fixed order.

Step 1: Divergence With P=x2yP=x^2y, Q=yz2Q=yz^2, and R=xzR=xz, โˆ‡โ‹…๐‘ญ=Px+Qy+Rz=2xy+z2+x.\nabla\cdot\mathbf F=P_x+Q_y+R_z =2xy+z^2+x. Thus โˆ‡โ‹…๐‘ญ=2xy+z2+x.\boxed{\nabla\cdot\mathbf F=2xy+z^2+x}.

Step 2: Curl โˆ‡ร—๐‘ญ=โŸจRyโˆ’Qz,Pzโˆ’Rx,Qxโˆ’PyโŸฉ=โŸจ0โˆ’2yz,0โˆ’z,0โˆ’x2โŸฉ.\begin{align*} \nabla\times\mathbf F &=\langle R_y-Q_z,\,P_z-R_x,\,Q_x-P_y\rangle\\ &=\langle 0-2yz,\,0-z,\,0-x^2\rangle. \end{align*} Therefore โˆ‡ร—๐‘ญ=โŸจโˆ’2yz,โˆ’z,โˆ’x2โŸฉ.\boxed{\nabla\times\mathbf F=\langle-2yz,-z,-x^2\rangle}.

Step 3: Evaluate At (1,2,โˆ’1)(1,2,-1), โˆ‡โ‹…๐‘ญ=6,โˆ‡ร—๐‘ญ=โŸจ4,1,โˆ’1โŸฉ.\boxed{\nabla\cdot\mathbf F=6}, \qquad \boxed{\nabla\times\mathbf F=\langle 4,1,-1\rangle}.

Verification The curl components follow the cyclic order (Ryโˆ’Qz,Pzโˆ’Rx,Qxโˆ’Py)(R_y-Q_z,P_z-R_x,Q_x-P_y); recomputing from the determinant form gives the same signs.