Green's Theorem — Question 3

Section 18-7 · Calculus pages 3465–3466

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Question 3

The planar field 𝑭(x,y)=⟨x2,xy⟩\mathbf F(x,y)=\langle x^2,xy\rangle acts on the disk D:(x−1)2+y2≤1D:(x-1)^2+y^2\le 1. Let C=∂DC=\partial D be counterclockwise. Find the outward flux of 𝑭\mathbf F across CC.

Tasks

  1. State the flux form of Green’s Theorem.

  2. Compute the divergence and its integral over DD.

  3. Use symmetry or the centroid of the disk to finish.

Question 3 – Solution

Strategy. Convert outward flux to the double integral of the planar divergence.

Step 1: Flux form For 𝑭=⟨M,N⟩\mathbf F=\langle M,N\rangle, ∮C𝑭⋅𝒏ds=∮CMdy−Ndx=∬D(Mx+Ny)dA.\oint_C\mathbf F\cdot\mathbf n\,ds =\oint_C M\,dy-N\,dx =\iint_D(M_x+N_y)\,dA. Here Mx+Ny=2x+x=3x.M_x+N_y=2x+x=3x.

Diagram shown in the original SVG worksheet.

Step 2: Integrate The disk has area π\pi and centroid (1,0)(1,0). Therefore its average xx-coordinate is 11, so ∬DxdA=1⋅π=π.\iint_Dx\,dA=1\cdot\pi=\pi. Consequently, ∮C𝑭⋅𝒏ds=∬D3xdA=3π.\boxed{\oint_C\mathbf F\cdot\mathbf n\,ds =\iint_D3x\,dA=3\pi}.

Verification The disk lies in 0≤x≤20\le x\le 2, so the divergence 3x3x is nonnegative. A positive outward flux is therefore consistent with the sign of the integrand.