Fundamental Theorem for Line Integrals — Question 2

Section 18-5 · Calculus pages 3423–3424

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Question 2

Let f(x,y)=x2+y2f(x,y)=x^2+y^2. A smooth curve CC travels from A=(3,4)A=(3,4) to B=(0,5)B=(0,5).

Tasks

  1. Evaluate ∫C∇f⋅d𝒓\displaystyle\int_C\nabla f\cdot d\mathbf r.

  2. Interpret the result using level curves of ff.

  3. Decide whether a different smooth path from AA to BB could change the value.

Question 2 – Solution

Strategy. Compare the potential values at the endpoints before doing any curve calculation.

Step 1: Endpoint values f(A)=32+42=25,f(B)=02+52=25.f(A)=3^2+4^2=25, \qquad f(B)=0^2+5^2=25. Hence ∫C∇f⋅d𝒓=f(B)−f(A)=0.\boxed{\int_C\nabla f\cdot d\mathbf r=f(B)-f(A)=0}.

Diagram shown in the original SVG worksheet.

Step 2: Interpret Both endpoints lie on the level circle x2+y2=25x^2+y^2=25. The curve between them need not stay on that circle: ff may rise and fall along the way, but its total change is still zero.

Step 3: Compare paths Any other smooth path with the same orientation from AA to BB gives the same endpoint difference, so it cannot change the integral.

Verification The result is not claiming that ∇f\nabla f vanishes. Indeed ∇f=⟨2x,2y⟩\nabla f=\langle 2x,2y\rangle is nonzero at both endpoints; only the net change in ff is zero.