Line Integrals of Vector Fields — Question 8

Section 18-4 · Calculus pages 3415–3416

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Question 8

Let CC be the counterclockwise boundary of the rectangle 0≤x≤20\le x\le 2, 0≤y≤10\le y\le 1. For 𝑭(x,y)=⟨y2,x⟩,\mathbf F(x,y)=\langle y^2,x\rangle, compute the circulation ∮C𝑭⋅d𝒓\displaystyle\oint_C\mathbf F\cdot d\mathbf r directly from the four edges.

Tasks

  1. Compute each oriented edge contribution.

  2. Add the four contributions.

  3. Check which signs are forced by the traversal direction.

Question 8 – Solution

Strategy. Write 𝑭⋅d𝒓=y2dx+xdy\mathbf F\cdot d\mathbf r=y^2dx+xdy and exploit the constant coordinate on each edge.

Step 1: Bottom and right Along the bottom, y=0y=0 and dy=0dy=0, so the contribution is 00. Along the right edge, x=2x=2 and y:0→1y:0\to 1, giving ∫012dy=2.\int_0^1 2\,dy=2.

Diagram shown in the original SVG worksheet.

Step 2: Top and left Along the top, y=1y=1 and counterclockwise travel has x:2→0x:2\to 0: ∫201dx=−2.\int_2^0 1\,dx=-2. On the left, x=0x=0, and dx=0dx=0, so the contribution is 00.

Step 3: Sum ∮C𝑭⋅d𝒓=0+2−2+0=0.\boxed{\oint_C\mathbf F\cdot d\mathbf r=0+2-2+0=0}.

Verification The right-edge contribution is positive because both the field’s vertical component and dydy are positive. The top contribution is negative because y2>0y^2>0 while dx<0dx<0; their equal magnitudes cancel.