Line Integrals - Part I — Question 7

Section 18-2 · Calculus pages 3373–3374

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Question 7

A wire follows the first-quadrant astroid arc 𝒓(t)=⟨cos⁡3t,sin⁡3t⟩,0≤t≤π2,\mathbf r(t)=\langle\cos^3t,\sin^3t\rangle, \qquad 0\le t\le\frac{\pi}{2}, and has linear density δ(x,y)=x+y\delta(x,y)=x+y. Find its mass.

Tasks

  1. Derive and simplify the speed on the given interval.

  2. Express the density in terms of tt and evaluate the mass.

  3. Check positivity and endpoint behavior.

Question 7 – Solution

Strategy. Differentiate the astroid parametrization; in the first quadrant the absolute values in the speed simplify.

Step 1: Speed

Diagram shown in the original SVG worksheet.

𝒓′(t)=⟨−3cos⁡2tsin⁡t,3sin⁡2tcos⁡t⟩.\mathbf r'(t)= \langle-3\cos^2t\sin t,\,3\sin^2t\cos t\rangle. Because sin⁡t,cos⁡t≥0\sin t,\cos t\ge 0, |𝒓′(t)|=3sin⁡tcos⁡tcos⁡2t+sin⁡2t=3sin⁡tcos⁡t.\begin{align*} |\mathbf r'(t)| &=3\sin t\cos t\sqrt{\cos^2t+\sin^2t}\\ &=3\sin t\cos t. \end{align*}

Step 2: Mass Along the wire, δ=cos⁡3t+sin⁡3t\delta=\cos^3t+\sin^3t. Hence M=∫0π/23(cos⁡3t+sin⁡3t)sin⁡tcos⁡tdt=3(∫0π/2cos⁡4tsintdt+∫0π/2sin⁡4tcostdt)=3(15+15)=65.\begin{align*} M&=\int_0^{\pi/2} 3(\cos^3t+\sin^3t)\sin t\cos t\,dt\\ &=3\left(\int_0^{\pi/2}\cos^4t\sin t\,dt +\int_0^{\pi/2}\sin^4t\cos t\,dt\right)\\ &=3\left(\frac 15+\frac 15\right)=\boxed{\frac 65}. \end{align*}

Verification Density and speed are nonnegative. The speed vanishes only at the two cusps, which does not affect the integral; the finite positive mass 6/56/5 is therefore consistent.