Line Integrals - Part I — Question 4

Section 18-2 · Calculus pages 3367–3368

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Question 4

Let CC be the helix 𝒓(t)=⟨2cos⁡t,2sin⁡t,t⟩,0≤t≤π.\mathbf r(t)=\langle 2\cos t,2\sin t,t\rangle, \qquad 0\le t\le\pi. Evaluate ∫C(x2+y2+z)ds.\int_C(x^2+y^2+z)\,ds.

Tasks

  1. Express the scalar function along the helix.

  2. Compute the speed and evaluate the integral.

  3. Verify the result by separating the constant and variable parts.

Question 4 – Solution

Strategy. Substitute the parametrization into both the scalar function and the arc-length factor.

Step 1: Restrict the integrand Along CC, x2+y2+z=4cos⁡2t+4sin⁡2t+t=4+t.x^2+y^2+z =4\cos^2t+4\sin^2t+t=4+t.

Diagram shown in the original SVG worksheet.

Step 2: Arc length and integral 𝒓′(t)=⟨−2sin⁡t,2cos⁡t,1⟩,|𝒓′(t)|=4+1=5.\mathbf r'(t)=\langle-2\sin t,2\cos t,1\rangle, \qquad |\mathbf r'(t)|=\sqrt{4+1}=\sqrt 5. Therefore ∫C(x2+y2+z)ds=5∫0π(4+t)dt=5[4t+t22]0π=5(4π+π22).\begin{align*} \int_C(x^2+y^2+z)\,ds &=\sqrt 5\int_0^\pi(4+t)\,dt\\ &=\sqrt 5\left[4t+\frac{t^2}{2}\right]_0^\pi =\boxed{\sqrt 5\left(4\pi+\frac{\pi^2}{2}\right)}. \end{align*}

Verification The constant part 44 contributes 4L=4π54L=4\pi\sqrt 5 because L=π5L=\pi\sqrt 5. The z=tz=t part has average π/2\pi/2 and contributes (π/2)L=π25/2(\pi/2)L=\pi^2\sqrt 5/2, matching the two terms above.