Double Integrals in Polar Coordinates — Question 10

Section 17-4 · Calculus pages 3219–3220

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Question 10

Let DD be the upper half-disk x2+y2≤9x^2+y^2\le 9, y≥0y\ge 0. Evaluate ∬D(x2+y2+xy)dA.\iint_D(x^2+y^2+xy)dA.

Tasks

  1. Convert the region and integrand to polar coordinates.

  2. Use angular symmetry to eliminate the mixed term.

  3. Evaluate the remaining integral and verify its sign.

Question 10 – Solution

Strategy. In polar form the radial term is r2r^2, while xy=r2cos⁡θsin⁡θxy=r^2\cos\theta\sin\theta cancels over 0≤θ≤π0\le\theta\le\pi.

Step 1: Set up 0≤θ≤π,0≤r≤3,0\le\theta\le\pi,\quad 0\le r\le 3, so I=∫0π∫03r3(1+cos⁡θsin⁡θ)drdθ.I=\int_0^\pi\int_0^3r^3(1+\cos\theta\sin\theta)\,dr\,d\theta.

Step 2: Symmetry Since ∫0πcos⁡θsin⁡θdθ=0,\int_0^\pi\cos\theta\sin\theta\,d\theta=0, the xyxy contribution vanishes, matching reflection symmetry across the yy-axis.

Step 3: Evaluate I=∫0π[r44]03dθ=∫0π814dθ=81π4.I=\int_0^\pi\left[\frac{r^4}{4}\right]_0^3d\theta =\int_0^\pi\frac{81}{4}d\theta =\boxed{\frac{81\pi}{4}}. The surviving integrand x2+y2x^2+y^2 is nonnegative, so the positive result is necessary. Its scale is radius squared times half-disk area, as expected.