Gradient Vector, Tangent Planes and Normal Lines — Question 2

Section 16-2 · Calculus pages 3063–3064

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Question 2

Let the level surface F(x,y,z)=xyez=2F(x,y,z)=xye^z=2 contain P=(1,2,0)P=(1,2,0).

Tasks

  1. Find the two unit normal vectors at PP.

  2. Write the tangent plane in standard form.

  3. Give symmetric or parametric equations for the normal line.

Question 2 – Solution

Strategy. Differentiate the defining level function; its gradient supplies both the plane normal and the normal-line direction.

Step 1: Gradient ∇F=⟨yez,xez,xyez⟩.\nabla F=\left\langle ye^z,xe^z,xye^z\right\rangle. At P=(1,2,0)P=(1,2,0), ∇F(P)=⟨2,1,2⟩,∥∇F(P)∥=3.\nabla F(P)=\left\langle 2,1,2\right\rangle,\qquad \|\nabla F(P)\|=3. Therefore the two unit normals are ±13⟨2,1,2⟩.\boxed{\pm\frac 13\left\langle 2,1,2\right\rangle}.

Step 2: Tangent plane 2(x−1)+(y−2)+2(z−0)=0,2(x-1)+(y-2)+2(z-0)=0, so 2x+y+2z=4.\boxed{2x+y+2z=4}.

Step 3: Normal line Using the unsimplified integer direction, (x,y,z)=(1,2,0)+t(2,1,2).\boxed{(x,y,z)=(1,2,0)+t(2,1,2)}. Equivalently, x−12=y−2=z2.\boxed{\frac{x-1}{2}=y-2=\frac z2}.

Verification The point satisfies 1⋅2⋅e0=21\cdot 2\cdot e^0=2. The line direction equals the plane’s coefficient vector, so it is perpendicular to the plane.