Vector Functions — Question 3

Section 14-6 · Calculus pages 2745–2746

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Question 3

A particle follows 𝒓(t)=⟨2cost,2sint,t/π⟩,0≤t≤4π.\mathbf r(t)=\left\langle 2\cos t,\ 2\sin t,\ t/\pi\right\rangle,\qquad 0\le t\le 4\pi. Without calculus:

  1. Describe the trace geometrically and state its axis and radius.

  2. Find every point where the particle meets the plane z=1z=1.

  3. Determine the vertical rise during one complete revolution and the total number of revolutions.

Question 3 – Solution

Strategy. Use the identity cos⁡2t+sin⁡2t=1\cos^2t+\sin^2t=1 and compare the angular parameter with the height.

Diagram shown in the original SVG worksheet.

Step 1: Cylindrical constraint x2+y2=4cos⁡2t+4sin⁡2t=4.x^2+y^2=4\cos^2t+4\sin^2t=4. Thus the trace lies on the cylinder of radius 22 about the zz-axis. Since z=t/πz=t/\pi steadily increases while (x,y)(x,y) rotates counterclockwise, the curve is a circular helix.

Step 2: Plane intersection Setting z=1z=1 gives tπ=1⇒t=π.\frac{t}{\pi}=1\quad\Longrightarrow\quad t=\pi. This value is in the interval, and therefore the only point is 𝒓(π)=⟨−2,0,1⟩.\boxed{\mathbf r(\pi)=\left\langle -2,0,1\right\rangle}.

Step 3: Pitch and turns One revolution changes tt by 2π2\pi, so Δz=t+2ππ−tπ=2.\Delta z=\frac{t+2\pi}{\pi}-\frac{t}{\pi}=2. The interval length 4π4\pi contains 4π/(2π)=24\pi/(2\pi)=2 revolutions. Hence the rise per turn is 2\boxed{2} and the curve makes 2\boxed{2} complete turns.