Spherical Coordinates — Question 9

Section 14-13 · Calculus pages 2897–2898

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Question 9

A point PP has spherical coordinates (ρ,θ,ϕ)(\rho,\theta,\phi) with ρ=10\rho=10 and is equally distant from the positive xx-, yy-, and zz-axes. Assume PP lies in the first octant.

Tasks

  1. Determine the Cartesian coordinates of PP.

  2. Find its principal spherical angles.

  3. Verify the three axis distances directly.

Question 9 – Solution

Strategy. Express squared distance to each coordinate axis and use first-octant signs.

Diagram shown in the original SVG worksheet.

Step 1: Equal-distance conditions Squared distances to the xx-, yy-, and zz-axes are y2+z2y^2+z^2, x2+z2x^2+z^2, and x2+y2x^2+y^2. Equality implies x2=y2=z2x^2=y^2=z^2. In the first octant, x=y=zx=y=z.

Step 2: Radius condition Since x2+y2+z2=100x^2+y^2+z^2=100, we obtain 3x2=1003x^2=100 and P=(10/3,10/3,10/3).\boxed{P=(10/\sqrt 3,10/\sqrt 3,10/\sqrt 3)}. Then θ=π/4\theta=\pi/4, and cos⁡ϕ=z/ρ=1/3\cos\phi=z/\rho=1/\sqrt 3, so (ρ,θ,ϕ)=(10,π/4,arccos⁡(1/3)).\boxed{(\rho,\theta,\phi)=(10,\pi/4,\arccos(1/\sqrt 3))}.

Verification. Every squared axis distance is 100/3+100/3=200/3100/3+100/3=200/3, so every distance is 102/3\boxed{10\sqrt{2/3}}.