The 3-D Coordinate System — Question 4

Section 13-1 · Calculus pages 2387–2388

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Question 4

The points A=(1,0,2)A=(1,0,2), B=(4,4,1)B=(4,4,1), and C=(−1,3,6)C=(-1,3,6) form a triangle. Classify it as scalene, isosceles, or equilateral, and determine whether it is acute, right, or obtuse.

Question 4 – Solution

Strategy Compare squared side lengths; this avoids unnecessary square roots. The converse of the Pythagorean theorem classifies the largest angle.

Diagram shown in the original SVG worksheet.

Side lengths Direct calculation gives AB2=32+42+(−1)2=26,AC2=(−2)2+32+42=29,BC2=(−5)2+(−1)2+52=51.AB^2=3^2+4^2+(-1)^2=26,\quad AC^2=(-2)^2+3^2+4^2=29,\quad BC^2=(-5)^2+(-1)^2+5^2=51. The three lengths differ, so the triangle is scalene.

Angle classification The longest side is BCBC. Since BC2=51<26+29=55BC^2=51<26+29=55, the angle opposite BCBC is acute. The other angles are necessarily smaller, so the triangle is scalene and acute\boxed{\text{scalene and acute}}.

Verification The triangle inequality holds; for example, 26+29>51\sqrt{26}+\sqrt{29}>\sqrt{51}.