Dot Product — Question 4

Section 12-3 · Calculus pages 2347–2348

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Question 4

A force F→=⟨12,−5⟩\vec F=\langle12,-5\rangle moves an object from (1,4)(1,4) to (7,1)(7,1). Find the work done.

Question 4 – Solution

Compute the dot product carefully, then choose the formula that matches the question. A zero, positive, or negative dot product also gives immediate geometric information.

Diagram shown in the original SVG worksheet.

The displacement is d→=⟨7−1,1−4⟩=⟨6,−3⟩\vec d=\langle7-1,1-4\rangle=\langle6,-3\rangle.

Work is the dot product: W=F→⋅d→W=\vec F\cdot\vec d.

Thus W=12(6)+(−5)(−3)=72+15=87W=12(6)+(-5)(-3)=72+15=\boxed{87} force-distance units.

The result follows from the defining vector formulas used above, and each component, magnitude, or scalar condition has been checked against the information in the question.

The dot product converts two vectors into a scalar measuring directional agreement: positive means generally aligned, zero means perpendicular, and negative means generally opposed.