Vector Arithmetic — Question 1

Section 12-2 · Calculus pages 2321–2322

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Question 1

Given u→=⟨2,−1,3⟩\vec u=\langle2,-1,3\rangle and v→=⟨−4,5,1⟩\vec v=\langle-4,5,1\rangle, find 3u→−2v→3\vec u-2\vec v and its magnitude.

Question 1 – Solution

Write every vector in matching component order. Perform scalar multiplication before addition or subtraction, then interpret the resulting components in the context of the problem.

Diagram shown in the original SVG worksheet.

Scale componentwise: 3u→=⟨6,−3,9⟩3\vec u=\langle6,-3,9\rangle and 2v→=⟨−8,10,2⟩2\vec v=\langle-8,10,2\rangle.

Subtract to get 3u→−2v→=⟨14,−13,7⟩3\vec u-2\vec v=\langle14,-13,7\rangle.

Its magnitude is 196+169+49=414=346\sqrt{196+169+49}=\boxed{\sqrt{414}=3\sqrt{46}}.

The result follows from the defining vector formulas used above, and each component, magnitude, or scalar condition has been checked against the information in the question.

Vector equations behave like ordinary algebra provided that every operation is performed component by component. A final component check is often the fastest verification.