Vectors - The Basics — Question 4

Section 12-1 · Calculus pages 2307–2308

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Question 4

The point P=(2,−1,4)P=(2,-1,4) is translated five units in the direction of a→=⟨−2,1,2⟩\vec a=\langle-2,1,2\rangle. Find the image point QQ.

Question 4 – Solution

Identify the initial and terminal information first. Build the vector by subtracting coordinates, then use the magnitude formula or normalize only after the components are correct.

Diagram shown in the original SVG worksheet.

First normalize: ∥a→∥=3\|\vec a\|=3, so â=13⟨−2,1,2⟩\widehat a=\frac13\langle-2,1,2\rangle.

A five-unit translation has vector 5â=⟨−10/3,5/3,10/3⟩5\widehat a=\langle-10/3,5/3,10/3\rangle.

Add it to PP: Q=P+5â=(−43,23,223)Q=P+5\widehat a=\boxed{\left(-\frac43,\frac23,\frac{22}3\right)}.

The result follows from the defining vector formulas used above, and each component, magnitude, or scalar condition has been checked against the information in the question.

A vector separates two ideas: its components describe displacement, while its magnitude and unit vector describe size and direction. Always check signs and confirm that a unit vector has magnitude 11.