Absolute Convergence and Divergence — Question 9

Section 11-9 · Calculus pages 2117–2118

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*Question 9 Consider ∑n=1∞(−1)n(1+1n)−n\displaystyle\sum_{n=1}^{\infty}(-1)^n\left(1+\frac1n\right)^{-n}.

  1. Find the limit of the magnitude.

  2. Apply the nth-term test.

  3. Explain why alternating signs cannot rescue the series.

*Question 9 – Solution

The standard exponential limit gives (1+1n)n→e,(1+1n)−n→e−1≠0.\left(1+\frac1n\right)^n\to e, \qquad \left(1+\frac1n\right)^{-n}\to e^{-1}\ne0.

Even-indexed terms approach e−1e^{-1} and odd-indexed terms approach −e−1-e^{-1}. Thus the terms do not approach zero.

A necessary condition for series convergence fails, so the series diverges. The AST is unavailable because its magnitude condition bn→0b_n\to0 fails.