Taylor Series — Question 3

Section 11-16 · Calculus pages 2245–2246

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*Question 3 Derive the Maclaurin series for cos⁡x\cos x from its derivative cycle. Explain why every odd coefficient vanishes, give the degree-66 polynomial, and state the convergence domain.

*Question 3 – Solution

cos⁡x,−sin⁡x,−cos⁡x,sin⁡x,…\cos x,\quad-\sin x,\quad-\cos x,\quad\sin x,\ldots gives values 1,0,−1,0,1,…1,0,-1,0,1,\ldots at 00. Therefore every odd-order coefficient is zero, and the even coefficients alternate in sign.

cos⁡x=∑n=0∞(−1)nx2n(2n)!,P6(x)=1−x22!+x44!−x66!.\boxed{\cos x=\sum_{n=0}^{\infty}\frac{(-1)^n x^{2n}}{(2n)!}},\qquad P_6(x)=1-\frac{x^2}{2!}+\frac{x^4}{4!}-\frac{x^6}{6!}.

Consecutive absolute terms have ratio x2(2n+1)(2n+2)→0,\frac{x^2}{(2n+1)(2n+2)}\to0, so the series converges for all xx. Since every derivative of cosine has magnitude at most 11, the Lagrange remainder is at most |x|m+1/(m+1)!→0|x|^{m+1}/(m+1)!\to0. Hence the series equals cos⁡x\cos x on (−∞,∞)(-\infty,\infty).