Power Series — Question 5

Section 11-14 · Calculus pages 2209–2210

Show solutionHide solution

*Question 5 Determine the radius and set of convergence of ∑n=0∞n!xn\displaystyle\sum_{n=0}^{\infty}n!x^n. Use the Ratio Test to show what happens for every nonzero xx.

*Question 5 – Solution

With an=n!xna_n=n!x^n, |an+1an|=(n+1)|x|→∞.\left|\frac{a_{n+1}}{a_n}\right|=(n+1)|x|\longrightarrow\infty. The Ratio Test therefore gives divergence for every fixed nonzero xx. Indeed, the terms eventually increase in magnitude and cannot tend to zero.

At x=0x=0, the series has only its n=0n=0 term nonzero (using 00=10^0=1 in the power-series convention), so it converges to 11.

The radius is R=0\boxed{R=0} and the set of convergence is the single point {0}\boxed{\{0\}}. This is not a nondegenerate interval.