Arc Length with Polar Coordinates — Question 7

Section 10-9 · Calculus pages 1893–1894

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Question 7

Problem

Find the length of r=eθr=e^\theta, 0≤θ≤ln⁡20\le\theta\le\ln2.

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Question 7 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Differentiate the polar radius to obtain r′=dr/dθr'=dr/d\theta and choose an interval that traces the requested arc exactly once.

  2. Use the polar arc-length formula L=∫abr2+(drdθ)2dθ.L=\int_a^b\sqrt{r^2+\left(\frac{dr}{d\theta}\right)^2}\,d\theta. Simplify the expression under the square root before evaluating or reporting the integral.

  3. Since r′=rr'=r, speed is 2eθ\sqrt2e^\theta.

  4. Thus L=2[eθ]0ln⁡2=2.L=\sqrt2[e^\theta]_0^{\ln2}=\boxed{\sqrt2}.