Area with Polar Coordinates — Question 6

Section 10-8 · Calculus pages 1871–1872

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Question 6

Problem

The curve r2=4cos⁡2θr^2=4\cos2\theta has two loops. Find its total area.

Diagram shown in the original SVG worksheet.

Question 6 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Determine an interval of angles that sweeps out the requested region exactly once, using symmetry when it simplifies the work.

  2. For a polar boundary r=f(θ)r=f(\theta), use A=12∫abr2dθ.A=\frac12\int_a^b r^2\,d\theta. For a region between two curves, subtract the inner squared radius from the outer squared radius before integrating.

  3. One loop uses −π/4≤θ≤π/4-\pi/4\le\theta\le\pi/4: area =12∫4cos⁡2θdθ=2=\tfrac12\int4\cos2\theta d\theta=2.

  4. Doubling gives 4\boxed{4}.