Area with Polar Coordinates — Question 4

Section 10-8 · Calculus pages 1867–1868

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Question 4

Problem

Find the common area of the circles r=2cos⁡θr=2\cos\theta and r=2sin⁡θr=2\sin\theta.

Diagram shown in the original SVG worksheet.

Question 4 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Determine an interval of angles that sweeps out the requested region exactly once, using symmetry when it simplifies the work.

  2. For a polar boundary r=f(θ)r=f(\theta), use A=12∫abr2dθ.A=\frac12\int_a^b r^2\,d\theta. For a region between two curves, subtract the inner squared radius from the outer squared radius before integrating.

  3. In the first quadrant the smaller radius switches at π/4\pi/4.

  4. Symmetry gives A=∫0π/4(2sin⁡θ)2dθ=π/2−1.A=\int_0^{\pi/4}(2\sin\theta)^2d\theta=\boxed{\pi/2-1}.