Tangents with Polar Coordinates — Question 5

Section 10-7 · Calculus pages 1849–1850

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Question 5

Problem

Find the tangent directions at the pole for the rose r=sin⁡3θr=\sin3\theta.

Diagram shown in the original SVG worksheet.

Question 5 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Write the polar curve parametrically as x(θ)=r(θ)cos⁡θ,y(θ)=r(θ)sin⁡θ.x(\theta)=r(\theta)\cos\theta, \qquad y(\theta)=r(\theta)\sin\theta. Differentiation gives dxdθ=r′cos⁡θ−rsin⁡θ,dydθ=r′sin⁡θ+rcos⁡θ.\frac{dx}{d\theta}=r'\cos\theta-r\sin\theta, \qquad \frac{dy}{d\theta}=r'\sin\theta+r\cos\theta.

  2. Wherever dx/dθ≠0dx/d\theta\ne0, compute dydx=r′sin⁡θ+rcos⁡θr′cos⁡θ−rsin⁡θ.\frac{dy}{dx}= \frac{r'\sin\theta+r\cos\theta} {r'\cos\theta-r\sin\theta}. Test numerator and denominator separately when locating horizontal or vertical tangents.

  3. The pole occurs when 3θ=kπ3\theta=k\pi, so the tangent rays satisfy θ=kπ/3\theta=k\pi/3.

  4. The distinct unoriented lines are θ=0,θ=π/3,θ=2π/3.\boxed{\theta=0,\quad\theta=\pi/3,\quad\theta=2\pi/3}.