Area with Parametric Equations — Question 5

Section 10-3 · Calculus pages 1769–1770

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Question 5

Problem

A simple, piecewise smooth closed curve is traversed once clockwise. Explain why ∫ydx\int y\,dx may be positive even though area cannot be negative.

Diagram shown in the original SVG worksheet.

Question 5 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. A line integral around a closed curve is signed: reversing the direction of traversal reverses the sign because dxdx changes sign.

  2. For a positively oriented, counterclockwise curve CC, Green’s theorem gives A=−∮Cydx.A=-\oint_C y\,dx. Thus ∮Cydx=−A\oint_C y\,dx=-A for counterclockwise traversal.

  3. If the same boundary is traversed clockwise, the line integral changes sign: ∮−Cydx=−∮Cydx=A.\oint_{-C}y\,dx=-\oint_Cy\,dx=A. Therefore, ∫ydx\int y\,dx can be positive for clockwise motion; the sign describes orientation, not a negative or positive physical area by itself.

  4. A direction-independent formula for geometric area is A=|∮Cydx|.\boxed{A=\left|\oint_C y\,dx\right|}. Equivalently, use −∮Cydx-\oint_Cy\,dx with counterclockwise orientation or reverse the bounds when necessary.