Solving Trig Equations with Calculators, Part I — Question 4

Section 1-5 · Calculus pages 97–98

Show solutionHide solution

Question 4

Solve the equation sin⁡(x)=−0.77\sin(x) = -0.77 for all x∈[0,2π]x \in [0, 2\pi], and round your answers to two decimal places.

Question 4 - Solution

Step 1: Isolate the trigonometric function. The equation becomes

sin⁡(1x)=−0.77,u=1x,0≤u≤2π.\sin(1x)=-0.77,\qquad u=1x,\qquad 0\le u\le 2\pi.

Let α=arcsin⁡(−0.77)\alpha=\arcsin(-0.77). All solutions are

u=α+2kπoru=π−α+2kπ,k∈ℤ.u=\alpha+2k\pi\quad\text{or}\quad u=\pi-\alpha+2k\pi,\qquad k\in\mathbb Z.

Step 2: Restrict and convert. Keep precisely the values of uu in [0,2π][0,2\pi] and divide by 11.

Evaluating the inverse function at full precision and rounding only the final values gives

x≈4.02,5.40.\boxed{x\approx 4.02,\ 5.40}.

These are all 2 solutions in the stated interval, in radians. Substitution of the unrounded values verifies the original equation.